Correct Answer: Option C

Explanation

V = I X\(_L\)

X\(_L\) = \(\frac{\text{V }}{\text{I}}\) = \(\frac{240}{2}\) = 120 Ω

But X\(_L\) = 2\(\pi\)fL

120 = 2 x 2\(\pi\) x \(\frac{100}{\pi}\) x L

120 = 2 x 100 x L = 200L

L = \(\frac{120}{200}\) = 0.6H

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