What is the escape velocity of a body on the surface of the Earth of radius R if the gravitational constant is G and the mass of the Earth is M? (Neglect energy losses to the surroundings)
a
\(\sqrt{(2GR^2}\)
b
\(\sqrt{(2GR)}\)
c
\(\sqrt{(2GM)}\)
d
\(\sqrt{(\frac{2G}{\text{R}})}\)
Explanation
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Cotech19
2 months ago
the correct answer is D:
ve=√2gR
F=mg=GMm/R2
g=GM/R2
gR=GMR/R2
=GM/R
so, ve=√2GM/R
