An air bubble of volume 2 cm\(^3\) is formed 20 m under water. What will be its volume when it rises to just below the surface of the water if the atmospheric pressure is equivalent to a height of 10 m of water?
P\(_1\) = 20 m + 10 m = 30 m = 3000 cm
V\(_1\) = 2 cm\(^3\)
P\(^2\) = 10 m = 1000 cm
V\(_2\) = ?
P\(_1\)V\(_1\) = P\(_2\)V\(_2\)
3000 × 2 = 1000 × V\(_2\)
V\(_2\) = \(\frac{3000 \times 2}{1000}\)
∴ V\(_2\) = 6 cm\(^3\)
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