A brass rod is 2 m long at a certain temperature. Calculate the linear expansion of the rod for a temperature change of 100 K. (Take linear expansivity of brass as 1.8 × 10\(^{-5}\) K\(^{-1}\))
L = 2 m; α = 1.8 × 10\(^{-5}\) K\(^{-1}\)); Δθ = 100 K
α = \(\frac{ΔL }{ (LΔθ)}\)
ΔL = α L Δ θ
ΔL = 1.8 × 10\(^{-5}\) x 2 x 100 = 3.6 x 10\(^{-3}\)
\(\therefore\) \(\Delta\) L = 0.0036m.
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