When a spiral spring is compressed by an external force of 200 N, it stores 0.16 J of energy. What amount of energy will it store when compressed by an external force of 700 N?

PerfectEmerole

4 months ago

E1= Fe/2
0.16 = 200×e1/2
0.32 = 200e1
e1 = 0.32/200 = 0.0016. we have gotten extension for the first body.
We know that weight or force of the body is directly proportional to extension.
W1/e1 = W2/e2
200/0.0016 = 700/e2
Cross multiply
1.12 = 200e2
e2 = 1.12/200 = 0.0056
Use energy formula.
E2= Fe/2
E2 = 700×0.0056/2
E2 = 1.96j option C

GoodluckOkolie

2 months ago

i go with the 1st solution

edutara

2 months ago

Don't you forget
It's 40 secs

Vico2106

2 months ago

It's too hard

Perpy21

3 months ago

please correct the final answer as it might mislead others who do not have proper understanding