Correct Answer: Option C

Explanation

The circuit is a simple series circuit with a 16 V battery (or voltage source) directly connected across a 2 Ω resistor.

The power (\(P\)) dissipated (developed) in the resistor is given by: \(P = \frac{V^2}{R}\)

where \(V = 16 \, \text{V}\) and \(R = 2 \, \Omega\).

Calculating the power: \(P = \frac{16^2}{2} = \frac{256}{2} = 128 \, \text{W}\)

There is an explanation video available below.

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