Assuming E\(_1\), E\(_2\), and E\(_3\), are equal, then the total e.m.f of the arrangement will be given by
a
\(\frac{1}{\text{E}}\) = (\(\frac{1}{E_1}\) +\(\frac{1}{E_2}\)) + E\(_3\)
b
E = \(E_1\) + \(E_2\) + \(E_3\)
c
\(\frac{1}{\text{E}}\) = \(\frac{1}{E_1}\) + \(\frac{1}{E_2}\) + \(\frac{1}{E_3}\)
d
E = \(E_1\) = \(E_2\) = \(E_3\)
Explanation
Correct Option
dVideo Explanation
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