Correct Answer: Option B

Explanation

Using Charles' law:

\(\frac{V_1}{T_1} = \frac{V_2}{T_2} \quad \text{(T in Kelvin, constant P)}\)

Calculate \( T_1 \): \(T_1 = 57 + 273 = 330 \, \text{K}\)

Since \( V_2 = \frac{1}{5} V_1 \) (volume shrinks to one-fifth), we find \( T_2 \):

\(T_2 = T_1 \times \frac{V_2}{V_1} = 330 \times \frac{1}{5} = 66 \, \text{K}\)

In °C, this is: \(T_2 = 66 - 273 = -207 \, °C\)

There is an explanation video available below.

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