Calculate the specific heat capacity of a metal rod of mass 0.025kg whose temperature was raised by 15ºC when 1000J of heat energy was added to the rod(assuming the heat loss to the surrounding is negligible)
D. 2666.7 \(\text{J kg}^{-1} \, \text{K}^{-1}\)
Using the formula: \(Q = mc\Delta T\)
We can rearrange to find \( c \): \(c = \frac{Q}{m \Delta T} = \frac{1000}{0.025 \times 15} = \frac{1000}{0.375} = 2666.7\)
Thus, the specific heat capacity is:
\(c = 2666.7 \, \text{J kg}^{-1} \, \text{K}^{-1}\).
There is an explanation video available below.
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