A machine has an efficiency of 80%. If the input work is 200J, the output work is?
\(\text{Efficiency} = \frac{\text{Output Work}}{\text{Input Work}}\)
Given: \(\text{Efficiency} = 80\% = 0.8\), \(\text{Input Work} = 200 \text{ J}\)
Then, the output work is calculated as follows:
\(\text{Output Work} = 0.8 \times 200 = 160 \, \text{J}\)
Thus, the output work is: \(\text{Output Work} = 160 \, \text{J}\).
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}