What magnitude of electric current can store 2.5 J of energy in a 3 H induction coil?

fabamz01

2 months ago

E=1/2*L*I^2

E=2.5j
L=3H
I=?

2.5=1/2*3*I^2

2.5=3/2*I^2

divide by the co efficient of I^2. which is 3/2

(2/3)*2.5=I^2


5/3= I^2
1.67=I^2

I= square root of 1.67
I= 1.29A

JClems

3 months ago

I'm confused 😕