A hydraulic press consists of two cylinders of cross-sectional radius r\(_1\) and r\(_2\). If a force of 200N applied to the smaller piston (r\(_1\)), causes a force of 3200N to be transmitted onto the larger piston (r\(_2\)). The ratio r\(_1\): r\(_2\) is?
a
1:4
b
1:2
c
1:8
d
1:16
Explanation
Correct Option
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Discussions (11)
PerfectEmerole
4 months ago
F1/F2 = (r1/r2)²
Where F1 is the smaller piston as it's where force is applied to overcome F2 as the load which is the larger piston
200/3200 =(r1/r2)²
Then dey ask us to find the ratio of r1 : r2
200/3200 = (r1/r2)²
1/16 = (r1/r2)²
√1/16 = r1/r2
1/4 = r1/r2
r1: r2
1 : 4 option A.
BlowBubblegum
3 months ago
Omo na people wey dey comment explanations I dey really understand from, may God bless all of you🙏🏽❤️
