A hydraulic press consists of two cylinders of cross-sectional radius r\(_1\) and r\(_2\). If a force of 200N applied to the smaller piston (r\(_1\)), causes a force of 3200N to be transmitted onto the larger piston (r\(_2\)). The ratio r\(_1\): r\(_2\) is?
Answer: A. 1:4
(Pressure equal: \(\frac{F_1}{(π r_1^2)}\) = \(\frac{F_2}{(π r_2^2)}\);
\(\frac{_r2}{r_1}\) = \(\sqrt{(F_2}{F_1)}\) = \(\sqrt{16}\) = 4.)
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