A student is at a height 4m above the ground during a thunderstorm. Given that the potential difference between the thundercloud and the ground is 10\(^7\)V, the electric field created by the storm is
A.
2.0 x 10\(^6\) NC\(^{-1}\)
B.
2.5 x 10\(^6\) NC\(^{-1}\)
C.
1.0 x 10\(^7\) NC\(^{-1}\)
D.
4.0 x 10\(^7\) NC\(^{-1}\)
Correct Answer: Option B
Explanation
E = \(\frac{V}{d}\)
E is the electric field (in volts per meter, V/m),
V is the potential difference (in volts, V),
d is the distance between the two points (in meters, m)
Given: Potential difference V = 10\(^7\)
Height d = 4m
That is, E = \(\frac{10^7}{4} = 2.5\times 10^6 NC^{-1}\)
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