Physics
JAMB 2001
A string is fastened tightly between two walls 24cm apart. The wavelength of the second overtone is
-
A.
24cm
-
B.
16cm
-
C.
12cm
-
D.
8cm
Correct Answer: Option B
Explanation
For a string fixed at both ends and plucked at the middle, the fundamental frequency is given
by f0 = v/λ, where v = velocity of sound, λ = wave length.
At its fundamental, note, the the length of the string is given l = λ/2, => λ0 = 2l, where λ0 = wave length fundamental note. for the first over tone, λ1 = l.
For the second over tone, λ2 = 21/3 = (2 x 24)/3 = 16cm.
i.e. λ2 = 16cm.
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