An object projected at an angle to a ground level has a time of flight 4 seconds to move through still air. Calculate the maximum height attained by the object.[g = 10ms\(^{-2}\)]

Chrisbridge

1 year ago

Or time to reach the ground from maximum height is 4/2 = 2 sec

T = √(2H/g )
2² = 2H/g

H = 4g/2 = 2g = 2 x 10 = 20 m

EmB01

10 months ago

OR
T = 2t, therefore t = T/2 = 4/2 = 2s
Using v = u - gt
where v = 0
0 = u - 10(2)
u = 20m/s

Max Height, H = u^2/2g
H = (20x20)/20
H = 20m