Correct Answer: Option A

Explanation

X\(_c\) = \(\frac{1}{2\pi FC}\)

X\(_c\) = \(\frac{1}{2 \times 3.142 \times 60 \times 2 \times 10^{-6}}\)

X\(_c\) = 1326.1192\(\Omega\)

I = \(\frac{\text{V}}{X_c}\)

I = \(\frac{150}{1326.1192}\) = 0.113A

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