A radio is operated by eight cells each of e.m.f. 2.0V connected in series. If two of the cells are wrongly connected, the net e.m.f. of the radio is
8V
10V
12V
16V
Explanation
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Now here is a BETTER explanation....
No of cells initially available ; 8 cells
E.m.f of EACH cell = 2V
If there are 8 cells initially given & the voltage is 2V each,therefore the TOTAL VOLTAGE across the circiut =8*2=16V
Now ,what current is expected to flow in the circuit ?
Applying V=IR,....16=i8=2A....
But two was found to be faulty....theerfore,6 cells will be used to find the E.M.F in the circuit...
E.M.F =2(the curent) * 6= 12 V !!
I hope it helps......
The formula to use is
Enet =(n -2m)E
n = number of cell
m= " " wrong cell
E= emf of the cell
n = 8, m=2 and E = 2v
: . Enet =(8-2(2))2
Enet=(8-4)2
Enet= (4)2
Enet=8v//
Ans is A.
I rest my case
The answer is wrong please fix it.
It's supposed to be like this:
Since 2 cells are wrongly connected, it will cancel out the effect of two other cells which are connected directly to it therefore, we have:
Net E.m.f=(8*2)-(2*2*2)
= 16-8
=8.
Hope this helps others.
y'all shouldn't get this wrong
the total number of batteries connected is 8 nót 6
that's why the ans is 12
try reading ya question well before answering and arguing
The answer should be A.
The tot. no. of correctly placed battery is 6.
Wrong placed battery is 2.
2*6-2*2=12-4=8V
The answer ought to be 8V (option A)
12v + {-2V + (-2V)}. Because 2 were connected Wrongly
12 V + (-4V)
8V
