Correct Answer: Option A

Explanation

Electric field intensity(E) = \(\frac{\text{Force}}{\text{charge}}\) = \(\frac{F}{q}\)

q = 4μC = 4.0 x 10\(^{-6}\)C

F = 8N

E = \(\frac{8}{4.0 \times 10^{-6}}\) = 2.0 x 10\(^6\)NC\(^{-1}\)

There is an explanation video available below.

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