Calculate the value of electric field intensity due to a charge of 4μC if the force due to the charge is 8N

a

2.0 x 10\(^6\)NC\(^{-1}\)

b

3.0 x 10\(^6\)NC\(^{-1}\)

c

4.0 x 10\(^6\)NC\(^{-1}\)

d

8.0 x 10\(^6\)NC\(^{-1}\)

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Correct Option
a

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Sensei
2 months ago

from NC ---> you know what to do 😈

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