The efficiency of a cell with internal resistance of 2\(\Omega\) supply current to a 6\(\Omega\) resistor is 

Mustpassexam

1 year ago

the answer is 75%

Sammykenny1

1 year ago

the answer is 75%, I think that was a mistake

Nzubecyprian

1 year ago

Check this Calculation, it is meant to be 6/8 not 2/8. U guys are wrong

Shulydave

1 year ago

Pls am not understanding

olorunjedacoker

1 year ago

the answer is 75

Elisha#God's genius

2 months ago

There's an error in the solution provided

De sage

1 year ago

yh it's a mistake

AyshahSS2A

4 months ago

you guys check out how I solved mine
I just did it the simple way; 6÷3=3. then since they

AyshahSS2A

4 months ago

you guys check out how I solved mine
I just did it the simple way; 6÷3=3. then since they are asking for percentage I just did 3 of 100 is 75 and that is how I got my answer

Eugene1097

1 year ago

interesting

Okekec602

1 year ago

the question correct but the answer is wrong