If the pressure on an enclosed gas is doubled and its temperature rises from 27ºC to 127ºC, then its volume will 

De sage

1 year ago

jamb una wicked 😫😫😫😫😫😫!!!!!

Emmanuel24458

1 year ago

i think A

purix

2 months ago

I still don't understand

Sensei

2 months ago

Simple

DidiM

1 year ago

shouldn't it be that it decreased by 1/3rd, since the new volume is 2/3 of the old volume.

melloxtre

3 months ago

Initial temperature:
𝑇
1
=
27
∘
𝐶
=
27
+
273
=
300
 
K
T
1
​

=27
∘
C=27+273=300K

Final temperature:
𝑇
2
=
127
∘
𝐶
=
127
+
273
=
400
 
K
T
2
​

=127
∘
C=127+273=400K

Pressure doubles:
𝑃
2
=
2
𝑃
1
P
2
​

=2P
1
​


Initial volume:
𝑉
1
V
1
​


Find: final volume
𝑉
2
V
2
​


Step 1: Use Combined Gas Law

The Combined Gas Law (from Boyle’s & Charles’s laws) is:

𝑃
1
𝑉
1
𝑇
1
=
𝑃
2
𝑉
2
𝑇
2
T
1
​

P
1
​

V
1
​

​

=
T
2
​

P
2
​

V
2
​

​


Where all temperatures are in Kelvin.

Step 2: Solve for
𝑉
2
V
2
​

𝑉
2
=
𝑃
1
𝑉
1
𝑇
2
𝑃
2
𝑇
1
V
2
​

=
P
2
​

T
1
​

P
1
​

V
1
​

T
2
​

​


Substitute
𝑃
2
=
2
𝑃
1
P
2
​

=2P
1
​

:

𝑉
2
=
𝑃
1
𝑉
1
𝑇
2
2
𝑃
1
𝑇
1
=
𝑉
1
𝑇
2
2
𝑇
1
V
2
​

=
2P
1
​

T
1
​

P
1
​

V
1
​

T
2
​

​

=
2T
1
​

V
1
​

T
2
​

​

𝑉
2
=
𝑉
1
×
400
2
×
300
=
400
600
𝑉
1
=
2
3
𝑉
1
V
2
​

=
2×300
V
1
​

×400
​

=
600
400
​

V
1
​

=
3
2
​

V
1
​

Answer:
𝑉
2
=
2
3
𝑉
1
V
2
​

=
3
2
​

V
1