Using the diagram above, calculate the relative density of x, if the density of methanol is 800kgm\(^{-3}\)
At equilibrium, the pressures at the bottom of both columns are equal:
ρ\(_m\) × h\(_m\) × g = ρ\(_x\) × h\(_x\) × g
g cancels out, so:
ρ\(_m\) × h\(_m\) = ρ\(_x\) × h\(_x\)
\(\rho_x = \rho_m \times \frac{h_m}{h_x} = 800 \times \frac{7.1}{14.2}\)
\(\frac{7.1}{14.2} = 0.5\)
\(\rho_x = 800 \times 0.5 = 400 \, \text{kg/m³}\)
Relative density of X (with respect to methanol) =
\(\frac{\rho_x}{\rho_m} = \frac{400}{800} = \mathbf{0.5}\)
There is an explanation video available below.
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