Correct Answer: Option C

Explanation

The magnetic force on an electron in a magnetic field (F) = q v Bsin\(\theta\)

B = 10T, q =  3 x 10\(^7\)m/, \(\theta\) = 60º and q =  1.6 x 10\(^{-19}\)C

F =  1.6 x 10\(^{-19}\) x 3 x 10\(^7\) x 10 x sin 60º \(\approxeq\) 4.162 × 10\(^{-11}\)N

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