Correct Answer: Option A

Explanation

The energy stored in the capacitor = \(\frac{1}{2}\)\(\frac{q^2}{C}\)

Where C = 2F, q = 3C

=  \(\frac{1}{2}\)\(\frac{3^2}{2}\) = \(\frac{9}{4}\) = 2.25J

There is an explanation video available below.

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