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A load of 300N is to be lifted by a machine with a velocity ratio...

Physics
JAMB 2024

A load of 300N is to be lifted by a machine with a velocity ratio of 2 and an efficiency of 60%. What effort will be applied to lift the load?

  • A. 100N
  • B. 150N
  • C. 250N
  • D. 400N
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Correct Answer: Option C
Explanation

Efficiency = \(\frac{\text{ M.A}}{\text{V.R}}\) x 100

M.A = \(\frac{\text{LOAD}}{\text{EFFORT}}\)

V.R = 2, Eff. = 60% = 0.6, Load = 300N

0.6 = \(\frac{\text{M.A}}{2}\)

M.A = 1.2

1.2 = \(\frac{300}{\text{E}}\)

Effort = \(\frac{300}{1.2}\) = 250N

There is an explanation video available below.


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Explanation Video

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