Correct Answer: Option C

Explanation

Given: mass of stone = 500g = 0.5kg, e = 20cm = 0.2m, velocity of stone on leaving the catapult = 40m/s

The potential energy stored in the catapult when extended = the kinetic energy (KE) of the stone

\(\frac{1}{2}\)Fe = \(\frac{1}{2}\)mv\(^2\)

F x 0.2 = 0.5 x 40 x 40 

F = \(\frac{800}{0.2}\) = 4000 N = 4 x 10\(^3\) N

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