The diagram above illustrates a mode of vibration of a wire of length 125 cm. The speed of the waves along the wire is 120 ms-1. Use the diagram to answer questions 2 and 3.
Number of cycles, n = \(2\frac{1}{2} = \frac{5}{2}\)
Length = nλ
λ = \(\frac{Length}{n}\) = \(\frac{125}{\frac{5}{2}}\)
Therefore, λ = 50cm = 0.50m.
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