From the diagram above, if the potential difference across the resistor, capacitor and inductor are 60V, 120V and 30V respectively, the effective potential difference is
\(V_L\)=60 V ,\(V_C\) = 120 V , \(V_R\) =30V
;V = ?
; \(V^2\) = \(V_R^2\) + \(V_L\) - \(V_C^2\)
= \(V^2\) = \(30^2\) + \(60 - 120^2\)
= \(V^2\) = 900 + 3600
= \(V^2\) = 4500
= V = √4500 = 67V
There is an explanation video available below.
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