An object is placed 35 cm away from a convex mirror with a focal length of magnitude 15 cm. What is the location of the image?
f= 15cm (diverging mirror); u= -35cm(because object is in front of the mirror) v=?
⇒\(\frac{1}{f}\) = \(\frac{1}{v}\) - \(\frac{1}{u}\)
⇒ \(\frac{1}{15}\) = \(\frac{1}{v}\) - \(\frac{1}{-35}\)
⇒ \(\frac{1}{15}\) - \(\frac{1}{35}\) = \(\frac{1}{v}\)
⇒ \(\frac{105}{4}\) = \(\frac{1}{v}\)
v = \(\frac{105}{4}\) = 26.25cm
∴The image is 26.25cm behind the mirror
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