An object is placed 35 cm away from a convex mirror with a focal length of magnitude 15 cm. What is the location of the image?
26.25 cm behind the mirror
10.5 cm behind the mirror
26.25 cm in front of the mirror
10.5 cm in front of the mirror
Explanation
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The new cartesian rule state
1. Distance meadured to the right of the mirror are positive.
2. Distance measured to the left of the mirror are negative.
3. Focal length of a concave mirror is negative
4. Focal length of a convex mirror is positive
(Refrerence: New school Physics)
Myshool pleaae correct this the answer is A
1/v = 1/15 - 1/35
1/v = 7-3/105
1/V = 4/105
V= 105/4
V= 26.25cm
since is a convex the image will be form behind the mirror
In this explanation, U is negative and that's not supposed to be. Although, your Ai explanation has already clarified me.
students must know that..
the object distance of a convex lens is always negative
That answer is wrong the correct answer is A because the signature was changed to + instead of -
And it is also a convex lense in between the focal length and pole which makes it a virtual image so the imagebus actually behind the mirror
Mirror Formula:
1/f = 1/do + 1/di
Given:
1. f = +15 cm (convex mirror)
2. do = 35 cm
Calculation:
1/15 = 1/35 + 1/di
1/di = 1/15 - 1/35
1/di = (7-3)/105
1/di = 4/105
di = 105/4
di = 26.25 cm
Image Location:
The image is located 26.25 cm behind the mirror (virtual image).
To find the location of the image formed by a convex mirror, we use the mirror formula:
1/f = 1/v + 1/u
f = is the focal length of the mirror (positive for a convex mirror).
V = is the image distance (to be calculated).
U = is the object distance (negative for mirrors, as the object is in front of the mirror).
Given:
f = +15 u = -35
Substitute into the mirror formula:
1/15= 1/v + 1/-35
Simplify:
1/v = 1/15 + 1/35
Find a common denominator (LCM of 15 and 35 is 105)
1/v = (7 + 3)/105
v = 105/10 = 10.5 cm
Final Answer:
B. 10.5 cm behind the mirror
f= 15cm
u= 35cm
V=?
1/f = 1/u + 1/u
f = (uv)/(u + v)
for convex mirror
- f = (uv)/(u+ v)
- 15 = 35V/35 + v
- 15 * 35 - 15v = 35v
- 525 = 35v + 15v
- 525 = 50v
- 525/50 = (50v)/50
- 10.5 = v
The negative sign indicated that a virtual image is formed which is always behind the mimor
