A piano wire 50 cm long has a total mass of 10 g and its stretched with a tension of 800 N. Find the frequency of the wire when it sounds its third overtone note.

123Ames

3 months ago

How can we solve this in unde 40s ?

Mudabobo

2 years ago

pls who can solve in simple way to understand better

Velapearl

2 months ago

Length = 50 cm = 0.5 m
Mass = 10 g = 0.01 kg
μ = m / L
μ = 0.01 / 0.5 = 0.02
Step 2: Find fundamental frequency
Formula:
f = (1 / 2L) × √(T / μ)
Now substitute:
2L = 2 × 0.5 = 1
T / μ = 800 / 0.02 = 40000
√40000 = 200
So:
f = (1 / 1) × 200 = 200 Hz
Step 3: Third overtone
Remember this simple rule:
1st overtone = 2f
2nd overtone = 3f
3rd overtone = 4f
So:
3rd overtone = 4 × 200 = 800 Hz
Final answer:
800 Hz

Emmanuel24458

2 years ago

Is D I got