Light of wavelength 589 nm in vacuum passes through a piece of fused quartz of index of refraction n = 1.458. What is the frequency of the light in fused quartz?
[Speed of light c = \(3.00×10^8 ms^{-1}\)]
a
\(5.09×10^{15}\)Hz
b
\(5.09×10^{14}\) Hz
c
\(1.77×10^{15}\) Hz
d
\(1.77×10^{14}\) Hz
Explanation
Correct Option
bVideo Explanation
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Discussions (13)
Odemosad
1 year ago
Since Frequency is same both in Vacuum and Medium, Accurate way is 
wavelength = 589nm = 5.89 x 10^-7
F = C / wavelength = (3 x 10^8) / (5.89 x 10^-7)
= 5.09 x 10^14 Hz
ochmandavidson
1 year ago
frequency doesn't change when light passes from one medium to another so if u solve for the frequency of the vacuum it is the same for the frequency of fused quartz
