An air bubble of radius 4.5 cm initially at a depth of 12 m below the water surface rises to the surface. If the atmospheric pressure is equal to 10.34 m of water, the radius of the bubble just before it reaches the water surface is
6.43 cm
8.24 cm
4.26 cm
5.82 cm
Explanation
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:
To solve this, we can apply Boyle's Law, which states that for a fixed amount of gas at constant temperature:
P1 V1 = P2 V2
Since the bubble is spherical, the volume is proportional to . So we can rewrite Boyle's law as:
P1( r1)^3 = P2 (r2)^3
Given:
Initial radius, cm
Initial pressure, atmospheric pressure + pressure due to 12 m of water
P1 = 10.34 + 12 = 22.34
Final radius
Apply the equation:
22.34 Γ (4.5)^3 = 10.34 Γ(r2)^3
22.34 Γ91.125 = 10.34 Γ(r2)^3
2035.96 = 10.34 Γ(r2)^3
(r2)^3 = {2035.96}Γ·{10.34} =196.86
r2 = 3β{196.86} =5.82 { cm}
Final Answer:
D. 5.82 cm
this is poo really. There's no cube root on jamb calculator. what do we do then? They're just giving questions someone would fail
when you don try to dey solve and you now see cube root of a rediculous figure and there is no calculator o
God help us in physics
Like my comment if you are writing your jamb in 2035
by then i would have married 
