How much net work is required to accelerate a 1200 kg car from 10\(ms^{-1}\) to 15\(ms^{-1}\)

a

1.95×\(10^5 j\)

b

1.35×\(10^4 j\)

c

7.5×\(10^4 j\)

d

6.0×\(10^4 j\)

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Explanation

Correct Option
c

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Discussions (15)

Odemosad
1 year ago

To find the net work required, we can use the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy.

work= 1/2m(v²-u²)


work= 1/2×1200×(15²−10²)

work = 600 × (225 -100)

work= 600 × 125

work= 7.5×10⁴J

Correct Option is C.

kairakizitor7
1 year ago

confusion 😭🙏

Ele0357
1 year ago

doing it directly can't give you ur answer 🥺

Monica08
2 months ago

clever

danis001
1 year ago

the guy explaining the answer is intelligent but He is too fast in doing calculations.

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