The surface temperature of a swimming pool on a warm day is 25ºC and the temperature at the bottom is 15ºC. If the swimming pool has a surface area of 620 \(m^2\) and a depth of 1.5m. Find the rate at which energy is transferred by conduction from the surface to the bottom of the swimming pool.
[Thermal conductivity of water (k) = 0.6071 Wm-1K-1]
2.5kw
250kw
300kw
3.0kw
Explanation
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Jst know the formula for thermal conductivity at least for now:
Q = (k * A * ΔT) / d
Where:
- Q is the heat transferred per unit time (in Watts, W)
- k is the thermal conductivity of the material (in W/m·K)
- A is the cross-sectional area (in m^2)
- ΔT is the temperature difference (in Kelvin, K)
- d is the depth or thickness or length of the material (in meters, m)
Hence, Q = 2509W = 2.5kW
Hope it helps 
Fourier's law of heat conduction
, this is unfair to us that just left secondary school na
it actually simple if you understand it
with the formula. boom 👊👊👊👊👊
I saw this type of question in 2024 then I force myself to know it and that is all
pls I'm confused on how to identify your first temperature between any given 2 temperatures as in this question (25 and 15) to find the change in temperature, bcus I thought is 15 -25 but I then see otherwise. 🙏 don't mind the English, just understand my question pls
