Correct Answer: Option D

Explanation

\(T_ {^1/_2}\) = 12 days ;V=?

\(T_ {^1/_2}\) = \(\frac{0.693}{γ}\)

⇒γ ⇒\(\frac{0.693}{t_{^1/_2}}\)

⇒γ =\(\frac{0.693}{12}\)

⇒γ= 0.05775 \(day^{-1}\)

There is an explanation video available below.

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