Correct Answer: Option A

Explanation

We first find the lorry's initial velocity
 

a = \(4ms^-2\), s= 250m,  t= 10,  u=?

⇒ ut +  \(\frac{1}{2}×4×(10^2)


⇒250= 10u + 200


⇒ 250-200 = 10u


⇒ 50 = 10u


⇒U =\frac{50}{10}\) = \(5ms^-1\)

For the next 10s, we set t=20s

= s = (5 × 20) + \(\frac{1}{2}×4×{20^2}\)

= s  = 100 + 800

⇒ 900 m

;Distance covered:900-250 =650m
 

There is an explanation video available below.

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