Correct Answer: Option D

Explanation

ε = 24.0 V,  r=1Ω,  R=5.0Ω

terminal p·d = ?

ε = IR+Ir = I(R+r) 

⇒ IR+Ir = I(R+r)
 
⇒ I = \(\frac{24}{5+1}\)

⇒ I =\(\frac{24}{6}\)

⇒ I = 4 A

terminal p·d = 4 × 5  

terminal p·d  =  20.0 V

There is an explanation video available below.

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