a
qVB sin\(\theta\)
b
\(\frac{\mu \phi I}{2 \pi r}\)
c
BA cos \(\theta\)
d
-N \(\frac{d \phi}{dt}\)
Explanation
Correct Option
cVideo Explanation
Post your Contribution
Share:
Discussions (6)
De sage
1 year ago
The expression for magnetic flux (Φ) is:
Φ = B × A × cos(θ)
where:
Φ = magnetic flux (in webers, Wb)
B = magnetic field strength (in teslas, T)
A = area of the surface (in square meters, m²)
θ = angle between the magnetic field and the normal to the surface
Alternatively, the expression can also be written as:
Φ = N × B × A × cos(θ)
where N is the number of turns of the coil.
