Consider the wave equation y = 5mm sin [1cm\(^{-1}\)x - 60s\(^{-1}\)t]. The wave number is?
0.1 cm\(^{-1}\)
10cm\(^{-1}\)
1.0cm\(^{-1}\)
2cm\(^{-1}\)
Explanation
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Discussions (16)
it's supposed to be D
using asin(2π×/∆ -wt)
where∆is wavelength 2π×/∆ =1x u'll get 2
if u try the same formula given ull get same answer
Okay for a better understanding this is the formula for the wave Equation 👉 y = sin [kx - ωt]
Where;
y: Displacement or amplitude of the wave
k: Wave number (related to wavelength)
x: Position or distance along the wave
ω (omega): Angular frequency (related to frequency)
t: Time
So from the question given...the wave number "k" is the coefficient of x in the equation
Which is C
hello
2πx/lambda =1cmx
using comparison method
2πx=1cmxλ
cancel out the common
x and x will go, then we have
2π= 1cmλ
λ= 2π/1
λ=2π
recall that
No of wave=2π/λ
but we have gotten our lambda as 2π
Wave number= 2π/2π
wave number=1
