If the kinetic energy of an electron is 100 eV, what is the wavelength of the de-Broglie wave associated with it? [h = 6.6 x 10\(^{-34}\) J s, e = 1.6 x 10\(^{-19}\)C, m\(_{e}\), = 9.1 x 10\(^{-31}\) kg]
1.22 x 10\(^{-10}\)m
4.10 x 10\(^{-10}\)m
3.90 x 10\(^{-10}\)m
5.50 x 10\(^{-14}\)m
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (8)
The selected answer is wrong.The correct answer is option A, 1.22× 10^-10m not 'D'
The k.E of the electron is 100eV meaning you are supposed to convert it to joules by multiplying it with 1.6×10^-19.
That is Ke = 100x1.6x10^-19
λ = h/p = λ/mv
K.E = 1/2mv²
how is λ = h/√2×m×K.E?🤨
because mv² = 2K.E
still wondering how my school got the formula
WAEC 2022 Physics objectives question 33 the selected answer is wrong.The correct answer is 1.22× 10^-10m ie 'A' not 'D'
The k.E of the electron 100eV suppose to be converted to joules by multiplying it with 1.6×10^-19.
