Physics
WAEC 2022
A lamp is rated 240 V, 60 W. Determine the resistance of the lamp when lit?
-
A.
120\(\Omega\)
-
B.
240\(\Omega\)
-
C.
540\(\Omega\)
-
D.
960\(\Omega\)
Correct Answer: Option D
Explanation
P = 60w, V = 240v, R = ?
P = \(\frac{V^2}{R}\)
: 60 = \(\frac{240^2}{R}\)
→ R * 60 = 57,600
R = \(\frac{57,600}{60}\)
R = 960\(\Omega\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}