The efficiency of a wheel and axle is 100% and the ratio of their radii is 5:1. calculate the effort required to lift a load of mass 20kg using this machine, [g = 10 m s\(^{-2}\)]

DamilolaOmojola

3 years ago

Since Efficiency is 100%
M.A = V.R
(L/E) = (2πR/2πr)
200/E = 5/1
5E = 200
E = 40N {C}

Odami11

3 years ago

Vr=5:1=5
Effort=?
Efficiency=100
Load=20kg
g=10m/s^2
Load=20×10=200
E=M.A/V.R×100
E=l/e/V.R×100
100/100=200/e/5
1/1=200/e×1/5
1/1=200/5e
5e÷5=200÷5
E=40N

TheLivingLegend01

3 years ago

The correct answer is B. 25N.

The mechanical advantage of a wheel and axle is given by the following equation:

MA = R/r

where MA is the mechanical advantage, R is the radius of the wheel, and r is the radius of the axle.

In this problem, the radius of the wheel is 5 times the radius of the axle. So, the mechanical advantage is:

MA = 5/1 = 5

The efficiency of the wheel and axle is 100%. This means that the work done by the effort is equal to the work done by the load. So, the effort required to lift a load of mass 20kg is:

E = W/MA = mg/MA = (20kg)(10 m/s²)/5 = 40N

However, the question asks for the effort required to lift the load using the wheel and axle. The mechanical advantage of the wheel and axle is 5, so the effort required to lift the load using the wheel and axle is:

E = 40N/5 = 25N

So the answer is B. 25N