A stone is thrown horizontally with initial velocity 15m/s from a tower 20 m high. How long does it take to reach the ground? [g= 10m/s\(^2\)

 

S.o.m.t.o

4 years ago

using square root of 2H/g = 2*20/10 =40/10=4
therefore take square root of 4 i.e 2s

Isabelle101

1 year ago

2s is the correct answer. Horizontal velocity has nothing to do with time taken, thus making u=0.

sulaimanharuna

4 years ago

Data
U=15m/s
H=20m
g=10m/s²
From; 2nd eqn. Of motion I.e h=u+1/2gt²
But u=0
.: 20=1/2×10×t²
t²=4
t=2s

heich

4 years ago

Thank you so much, I totally forgot about that formula

Favouronyedikachi64

2 years ago

initial velocity=15
: 20 - 15=5
g=10
10÷5=2

Tuki1

2 years ago

the answer is C

KOREDE.10

10 months ago

no explanation

Hussyred

1 year ago

u guys are all wrong the answer er is not even there the ancer is 15 secs
here's why
using ugcos tita minus ug sintita the ancer will give u 125 which is t squared if u square root both sides the answer will give u 15 secs thanks

Oluwabukunmi287

3 years ago

the answer is just 1s