Correct Answer: Option B

Explanation

f\(_{0}\) = 40H\(_{3}\)

1st overtone = 2f\(_{0}\) = 80H\(_{3}\)

2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)

3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)

4th overtone = 5f\(_{0}\) = 200H\(_{3}\)

\(\therefore\) Number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3

There is an explanation video available below.

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