A gas at a volume of V\(_{0}\) in a container at pressure p\(_{0}\) is compressed to one-fifth of its volume. What will be its pressure if the magnitude of its original temperature T is constant?
\(\frac{p_{0}} {5}\)
\(\frac{4p_{0}}{5}\)
p\(_{0}\)
5P\(_{0}\)
Explanation
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Discussions (11)
i have a little contribution to question, Which I think is more easier to tackle the Question,,.
since Boy's law stated that PRESSURE IS INVERSELY PROPORTIONAL TO VOLUME
which means if the Pressure increases , Volume will definitely decreases. Vice versa,,
then the question stated that the new volume decreases by 1/5 of its original volume,,
therefore the new pressure should be otherwise. i.e new pressure will increase by 5 of its original pressure.
mathematically
V2= V0/5 ( decrease by 5) then.
P2= P0 x 5 (increase by 5)
Note "Inversely proportional"...
if we understand it vary well, i believed, at a glance at the question, we can be able to choose the right option without touching our pen 
please what's your view about it,, Thanks
The answer are correct but the explanation is sometimes blurry and non understandable 😫😫
Given,
Vo
Po
V2=1/5Vo
P2=? 😭
V1P1=V2P2
Applying this formula to this question, we have
VoPo=1/5×Vo×P2
Vo will cancel out from both sides leaving only
Po=1/5×P2
Cross multiply
We then have
5Po=P2
That is,
P2=5Po😂
✌️
I feel there was a typo error in the em the solution becos if p0v0/p0/5 then the answer should be 5v0 but there is written as 5p0 so please check again. I mean no insults please this is just my suggestion no bad comments
