
- Measure and record the length XY of the resistance wire provided.
- Connect the circuit shown in the diagram.
- With R= O\(\Omega\), close the key, K. Read and record the current 1\(_{o}\) and the voltage drop V\(_{o}\) across the resistance wire.
- Setting R = 1\(\Omega\). close the key. Read and record the current, I, and the corresponding voltage drop, V across the wire.
- Repeat the procedure for five other values of R= 5, 10, 20, 40, and 60\(\Omega\). Tabulate your readings.
- Plot a graph of V on the vertical axis against 1 on the horizontal axis.
- Determine the slope of the graph
- State two precautions taken to ensure accurate results.
(b)i. Mention and state the law on which the experiment in (a) is based.
ii. A piece of resistance vire of diameter 0.2 mm and resistance m has a resistivity of 8.8 x 10\(^{-7}\)\(\Omega\)m, calculate the length of the Wire. [\(\pi\) =\(\frac{22}{7}\)]
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rachaelwillliam
2 years ago
Area of cross-section of wire =(3.1×10^-8)m² since
0.031 square millimetre(0
.031mm²)=
3.1 × 10⁻⁸ square metre(3.1×10^-8)
Resistivity = RA/L, length (L) = R.A/resistivity
L= (7×3.1×10^-8)÷(8.8×10^-7)
L= 0.2466
L=2.466×10^-1m

