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  1.  Measure and record the length XY of the resistance wire provided.
  2. Connect the circuit shown in the diagram.
  3. With R= O\(\Omega\), close the key, K. Read and record the current 1\(_{o}\) and the voltage drop V\(_{o}\) across the resistance wire.
  4. Setting R = 1\(\Omega\). close the key. Read and record the current, I, and the corresponding voltage drop, V across the wire.
  5. Repeat the procedure for five other values of R= 5, 10, 20, 40, and 60\(\Omega\). Tabulate your readings.
  6. Plot a graph of V on the vertical axis against 1 on the horizontal axis.
  7. Determine the slope of the graph
  8. State two precautions taken to ensure accurate results.

(b)i. Mention and state the law on which the experiment in (a) is based.

ii. A piece of resistance vire of diameter 0.2 mm and resistance m has a resistivity of 8.8 x 10\(^{-7}\)\(\Omega\)m, calculate the length of the Wire. [\(\pi\) =\(\frac{22}{7}\)]

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rachaelwillliam
2 years ago

Area of cross-section of wire =(3.1×10^-8)m² since
0.031 square millimetre(0
.031mm²)=
3.1 × 10⁻⁸ square metre(3.1×10^-8)
Resistivity = RA/L, length (L) = R.A/resistivity
L= (7×3.1×10^-8)÷(8.8×10^-7)
L= 0.2466
L=2.466×10^-1m

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