(b)i. Define the term couple as it relates to rotational or oscillatory systems.
ii. Give two practical application of a couple in everyday life.
Center of gravity C = 49.5cm
Mass of metre rule (MR) = 135g, d = 80cm = 0.8m
| h(cm) | d(m) | t(sec) | T=\(\frac{\text{t(sec)}}{20}\) | T\(^{2}\)(Sec\(^{2}\)) |
| 40 | 0.8 | 28.0 | \(\frac{28.0}{20}\)=1.40 | 1.9600 |
| 50 | 0.8 | 29.0 | \(\frac{29.0}{20}\)=1.45 | 2.1025 |
| 60 | 0.8 | 31.0 | \(\frac{31.0}{20}\)=1.55 | 2.4025 |
| 70 | 0.8 | 34.0 | \(\frac{34.0}{20}\)=1.70 | 2.8900 |
| 80 | 0.8 | 37.0 | \(\frac{37.0}{20}\)=1.85 | 3.4225 |
Slope (s) = \(\frac{\bigtriangleup {T}^{2}}{\bigtriangleup {h(cm)}}\) = \(\frac{(3.42-0.40)sec^{2}}{(80-21)cm}\)
= \(\frac{3.02sec^{2}}{59cm}\)
= 0.0512sec\(^{2}\)cm\(^{-1}\)
K = \(\frac{S}{Q}\), Q = \(\frac{2}{25d^{2}}\)
K = \(\frac {\frac{S}{2}}{25d^{2}}\)
S = 0.0512sec\(^{2}\)cm\(^{-1}\), d = 50cm = 0.8cm
K = \(\frac{0.0512sec^{2}cm^{-1} \times 25 \times (0.80)^{2}}{2}\)
K = \(\frac{0.0512 \times 25 \times 0.6400sec^{2}cm^{-1}}{2}\) = 0.4096sec\(^{2}\)cm\(^{-1}\)m\(^{2}\)
Precautions: i
- ensured smooth and regular oscillations in a horizontal plane.
- ensured there was no error due to parallax when reading my stopwatch.
(b)i. Couple -This can be defined as two forces of the same magnitude acting in opposite directions but not on the same line.
ii. Practical application of couple include:
- Opening or closing taps.
- Turning a spanner.
- Setting a flywheel in motion about an axis through its center
- Motion of a spinning spindle.
- Riding/pedaling of bicycle
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}