When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by
a
E = E\(_1\) + E\(_2\)
b
\(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
c
E = E\(_1\) = E\(_2\)
d
E = \(\frac{E_1}{E_2}\)
Explanation
Correct Option
cVideo Explanation
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Discussions (11)
abdulsalam.saliu
4 years ago
MySchool please endeavour to correct this error. The correct answer is C. E=E1=E2 for parallel connection of the cells. Ref: New School Physics Pg.396, Topic: Current Electricity.
BOBTHEBOY
1 year ago
myschool the answer is d the explanation is correct but the option chosen is wrong
